An impulse of 150 n s is required to stop a person's head in a car collision. if the face is in contact with the steering wheel for 0.0307 s, what is the average force on the cheekbone? answer in units of n.

We can divide the impulse by the time to determine the average force. Given an impulse of 150 N-s, and a contact time of 0.0307 s, the average force is:
150 N-s / 0.0307 s = 4886 N

Note that the impulse is the change in momentum, so they have the same units of N-s or kg-m/s.

The answer to this is decibel

Ithink the answer would be a