A3.00-kg model airplane has velocity components of 5.00 m/s due east and 8.00 m/s due north. what is the plane’s kinetic energy?

Kinetic energy, E = 133.38 Joules

Explanation:

It is given that,

Mass of the model airplane, m = 3 kg

Velocity component, v₁ = 5 m/s (due east)

Velocity component, v₂ = 8 m/s (due north)

Let v is the resultant of velocity. It is given by :

Let E is the kinetic energy of the plane. It is given by :

E = 133.38 Joules

So, the kinetic energy of the plane is 133.38 Joules. Hence, this is the required solution.

The plane’s kinetic energy is about 134 J

Let's recall the Kinetic Energy formula:

Ek = kinetic energy ( J )

m = mass of object ( kg )

v = speed of object ( m/s )

Let us now tackle the problem!

Given:

mass of model airplane = m = 3.00 kg

velocity component in the east direction = v_x = 5.00 m/s

velocity component in the north direction = v_y = 8.00 m/s

Asked:

kinetic energy of the plane = Ek = ?

Solution:

Firstly , we will find the resultant velocity as follows:

Next, we could calculate the plane's kinetic energy by using following formula:

Grade: High School

Subject: Physics

Chapter: Energy

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