When 1mol of a gas burns at constant pressure, it produces 2428 j of heat and does 6 kj of work?

The gas that experiences combustion yields 2428 J of heat, which suggests that q will be negative.

q=−2428 J

Similarly, work done by the system means that work was done by the gas on the surrounds, which once again suggests a minus sign.

w=−6 kJ

Since the gas burns at constant pressure, the heat given off will also be the enthalpy change, ΔH

ΔH=q → at constant pressure;

Change J to kJ to get

2428J x 10^−3kJ/ 1J = 2.428 kJ

Since you're distributing with 1 mole, you can write:

ΔH=−2.428 kJ/mol

Now use this equation to determine ΔE

ΔE=q+w

ΔE=−2.428 kJ+(−6 kJ)=−8.428 kJ

nec chapter 5 contains

c. information on special occupancy areas

nec chapter 6 covers

a. special equipment

which of the following rules contain the words shall or shall not and must be adhered to?

b. mandatory rules

which of the following rules identify actions that are allowed but not required and typically cover options or alternative methods?

c. optional rules

which of the following serves as the introduction to the nec and provides an overview of the book?

a. nec article 90

organizations that test products for safety are

c. nrtls

the nec is published by the

a national fire protection association

the nec is divided into

b. 9 chapters

the nec provides informative annexes for

c. informational materials and examples

two terms from nec article 100 that trainees should become familiar with are

b. labeled and listed

explanation: