Physics, 25.07.2019 10:50 MCMarioandLuigi

A40 g super ball strikes a wall with a velocity of 10 m/s that is normal to the wall it bounces away at a velocity of 7 m/s so normal to the wall what is the boss change in momentum is the ball bounces last is. one seconds what is the force between the ball and the wall

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The measurement of mass in motion is called momentum. The change in the momentum of the ball will be 0.68kgm/sec. While the force that acts on the body will be 0.68 N.

What is momentum?

The measurement of mass in motion is called momentum. Momentum is equal to its mass multiplied by its velocity. Mathematically it is given as;

Momentum = Mass x Velocity

The given data in the problem is

ball mass ( m)= 40 g=0.040 kg

speed of the ball(v) = 10 m/s

rebound speed(V )= -7 m/s

The change in the momentum of the body is given by,

Δp = mv - mv'

Δp= 0.040 x 10 - 0.057 x (-7)

ΔP = 0.68 kg.m/s

Hence the change in the momentum of the body will be 0.68 kg.m/s.

Impulse is defined as the product of force and time interval of contact.

$\rm I=F\times t\\\\\rm F=\frac{I}{t} \\\\\rm F=\frac{0.68}{1}\\\\ \rm F=0.68 N$

Hence the force that acts on the body will be 0.68 N.

To learn more about the momentum refer to the link;

link

Answer from: Brycen0

... The change in the ball's momentum is

(40 g) x (10 m/s + 7 m/s) = (40 g) x (17 m/s)

= 680 gram-m/s

Since we have to work with the impact formula in the next part,
we ought to change the grams in this answer to kilograms.

680 gram-m/s = 0.68 kg-m/s .

... If the ball is in contact with the wall for one second, then the
force exerted on the ball by the wall is found by remembering
that the change in momentum is equal to the impact (force x time) .

0.68 kg-m/s = (force) x (1 sec)

Divide each side by 1 sec :

0.68 kg-m/s² = 0.68 Newton = the Force

And now, if I may take the liberty of making a suggestion . . .
You need to remember the many benefits of "proofreading".
That is, before you post your question, look back and read
what you have written. That way, you have the chance to
correct any accidental mistakes that may have snuck into it,
and make it a lot easier for others to read the question and
come up with an answer.

I have to confess, I'm not completely sure of what your question is.
I know that what I have written is correct, but I honestly can't be sure
that it answers the question you asked.

Answer from: Quest

this isn't the answer but they're the graphs

Answer from: Quest

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

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A40 g super ball strikes a wall with a velocity of 10 m/s that is normal to the wall it bounces away...

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