Physics, 28.09.2019 08:00 maddyclark19

Without using the word or word forms of "motion",describe how you know and object is in motion

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You must look at the object either two or three times,
as follows:

1). Look at it the first time. Make a mental note, or take a photo,
of its location.

2). Wait a short time.

3). Look at the object the second time. Make another mental note,
or take another photo, of its position.

4). Compare the two photos or mental notes.

5). If the two images show the object in different places, then the object
is in motion RELATIVE TO YOU, and your investigation is finished. STOP.

6). If the two images show the object in the same identical place, then
you don't know the answer yet. It might be moving in a circle. You must
check it out.

7). Repeat step-1.

8). Repeat step-2, but wait a different length of time this time.

9). Repeat step-3. This gives you a third photo.

10). Compare the first and third photos.
. . . . . If these are still identical, you can be pretty sure that
the object is not in motion RELATIVE TO YOU.
. . . . . If these are different, then the object is in motion RELATIVE TO YOU.

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

Answer from: Quest

Sorry i don’t know what to do

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Without using the word or word forms of "motion",describe how you know and object is in motion...

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