Physics, 23.07.2019 04:00 MacieKay8865

During a baseball game, a batter hits a high pop-up. if the ball remains in the air for 6.0 s, how high does it rise? hint: calculate the height using the second half of the trajectory.

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Due that we don't know the initial speed after hitting the ball, we are going to accept that the ball goes up for half of the time and then falls during other half part, that is 3.0 seconds each. Then we know that ball's movement is ruled by the acceleration of gravity formula, as follows: H = Vi * T + 1/2 * g * T^2 V = Vi + g * T where: H is height, Vi initial speed, g gravity acceleration and T time When we only consider the second half of the trajectory, we have that initial speed at the top of that movement is zero, because ball goes up till top, where stops and starts to go down, so : H = 0 * 3 + 1/2 * 32 * 3^2 = 144 ft. So the height of the pop-up is 144 feet.

Answer from: kerarucker12pe384k

The maximum height reached by the baseball is 44.1 m

The given parameter:

time for the entire motion of the baseball = time spent in air, T = 6.0 s

time to reach the maximum height, $t = \frac{1}{2} \times 6 \ s = 3\ s$

To find:

the maximum height traveled by the baseball,

The maximum height reached by the baseball using second half of the trajectory is calculated as;

$h = ut + \frac{1}{2} gt^2$

where;

u is the initial velocity = 0

$h = \frac{1}{2} gt^2\\\\h = 0.5 \times 9.8 \times 3^2\\\\h = 44.1 \ m$

Thus, the maximum height reached by the baseball is 44.1 m

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Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

Ithink it is letter b, i may be wrong but i think that is the answer

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During a baseball game, a batter hits a high pop-up. if the ball remains in the air for 6.0 s, how h...

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