An apparatus like the one cavendish used to find g has a large lead ball that is 7.7 kg in mass and a small one that is 0.061 kg. their centers are separated by 0.05 m. find the force of attraction between them. the value of the universal gravitational constant is 6.67259 × 10−11 n · m2 /kg2 . answer in units of n.

The force of attraction between them is

Explanation:

We are going to use the Newton's Gravitational Law to solve this exercise.

The law states that :

The gravitational force between two objects is proportional to their masses and inversely proportional to the square of the distance between their centers.

The equation is :

Where '''' is the universal gravitational constant.

Where '''' and '''' are the masses of the objects.

Where '''' is the distance between the centers of the objects.

If we replace all the data in the equation :

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.