Awoman pushes a 27 kg lawnmower at a steady speed. she exerts a 180 n force in adirection 31 degrees below the horizontal. the acceleration of gravity is 9.8 m/^2find the magnitude of the vertical force this lawnmower exerts on the lawn. answer in units of n.

The solution for this problem is computed by:

We must look for the weight of the lawnmower = mg = 27 x 9.8 = 264.6 N 

Then look for the component of exerted force in downwards direction = 180 sin (31) = 92.71 N 

Total downwards force = 264.6 + 92.71 = 357.31 N 

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form