A0.500-kg ball traveling horizontally on a frictionless surface approaches a very massive stone at 20.0 m/s perpendicular to wall and rebounds with 70.0% of its initial kinetic energy. what is the magnitude of the change in momentum of the stone?

The magnitude of the change in momentum of the stone is about 18.4 kg.m/s

Let's recall Impulse formula as follows:

where:

I = impulse on the object ( kg m/s )

∑F = net force acting on object ( kg m /s² = Newton )

t = elapsed time ( s )

Let us now tackle the problem!

Given:

mass of ball = m = 0.500 kg

initial speed of ball = vo = 20.0 m/s

final kinetic energy = Ek = 70% Eko

Asked:

magnitude of the change of momentum of the stone = Δp = ?

Solution:

Firstly, we will calculate the final speed of the ball as follows:

→ negative sign due to ball rebounds

Next, we could find the magnitude of the change of momentum of the stone as follows:

Grade: High School

Subject: Physics

Chapter: Dynamics