15 points for 2 questions 1. your family is moving to a new home. while lifting a box 1.5m straight up to put it on a truck, you exert an upward force of 200n. calculate the amount of work you did. a) 133j b) 198.5j c) 201.5j d) 300j 2. a truck pulls a trailer at a constant velocity for a 100m while exerting a force of 480n. calculate the work done. a) 4.8j b) 380j c) 48,000j d) 580j

1. D) 300 J

The work done by a constant force is given by:

where F is the force applied, d is the distance, and is the angle between the direction of the force and the direction of motion.

In this problem, F=200 N, d=1.5 m while , because the force is parallel to the motion of the box, therefore the work done is

2. C) 48,000 J

We can use the same formula used in the previous part of the problem:

In this case:

F=480 N

d=100 m

So the work done is

its c i just checked it

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.