Otto emissions is driving his car at 25.0m/s. otto accelerates at 2.0 meters per seconds squared for 5 seconds. otto then maintains a constant velocity for 10 more seconds. determine the distance otto traveled during the entire 15 seconds

Given:
25.0 m/s -speed of his car
2.0 m/s^2 for 5s - acceleration
10s- constant velocity

Asked: total distance traveled during the entire 15 seconds.
( see attached file for the solution)

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !

Ultra-high temperature (uht)