Aquarterback back pedals 2.2 meters southward and then runs 6.8 meters northward, what is the distance, the magnitude, and direction?

The total distance covered by the cyclist is 9 m, while the displacement is 4.6 m northwards.

The given parameters;

Distance is scalar quantity. That is, distance can be represented in a complete sense with magnitude only.

The total distance covered during the motion = 2.2 m + 6.8 m = 9m

The direction describes the position of the total displacement.

The displacement = (6.8 m - 2.2 m) northward

The displacement = 4.6 m northward.

Thus, we can conclude that the total distance covered by the cyclist is 9 m, while the displacement is 4.6 m northwards.

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Distance moved = 9.0 m

Displacement magnitude = 4.6 m

Direction : Northwards

Explanation:

the quarter back pedals 2.2 m South

Then he pedal 6.8 m North

So here we can say that total distance moved by the quarterback is

Now to find the displacement we need to add them with direction

so we have

Direction : Towards North

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your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

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pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y