The particle moves first along the y axis from the origin to the point (0,6m) and then parallel to the x axis until it reaches (3m,6m). it is subject to a force f⃗ =cxyi^+dj^, where c = 8.0 n/m2 and d = 13 n . calculate the work done by the force. express your answer using two significant figures.

First we calculate the force.

F = 8 *3 * 6 i + 13 j = 144 i + 13 j

F = sqrt (144^2 + 13^2) = 144.59 N

Then calculate the displacement d.

d = sqrt (3^2 + 6^2) = 6.71 m

Work is the produce of force and displacement, therefore:

W = F d = 144.59 N * 6.71 m

W = 970 J

your answer would be fusion

momentum of soft ball three times less than baskey ball