Acar traveling at 34 m/s runs out of gas while traveling up a 5.0 â slope. how far will it coast before starting to roll back down?

Angle = 5°
Acceleration = a = g x Sin(θ) where g = 9.8m/s² = 9.8*Sin(6) = 0.854 m/s² ,

As coasting comes to a stop: 

v = a x t = 0 

t = v/a = 34/0.854 = 39.8 seconds 

The distance traveled is: 

d = (vf-vi)t - (1/2)at² = 34 x 39.8 - (1/2)(0.854)(39.8)² = 1353.2 -676.4
= 676.8 m