Two thin rods of length L are rotating with the same angular speed, W (in rad/s) about axes that pass perpendicularly through one end. Rod A is massless but has particle of mass 0.63 kg attached to its free end. Rod B has mass of 0.63 kg, which is distributed uniformly along its length. The length of each rod is 0.82 m, and the angular speed is 4.2 rad/s. Find the kinetic energies of rod A with its attached particle and of rod B.

Rod A: 3.74 J

Rod B: 3.74 J

STEP-BY-STEP EXPLANATION:

Rod A:

Length of the Rod = l = 0.82 m

Mass of particle attached = m = 0.63 kg

Moment of inertia of the system about given axis:

Angular speed of the rod = 4.2 rad/s

Kinetic energy of the rod is:

Rod B:

Length of the Rod = l = 0.82 m

Mass of particle attached = m = 0.63 kg

Moment of inertia of the system about given axis:

Angular speed of the rod = 4.2 rad/s

Kinetic energy of the rod is:

absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

explanation:

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle