PART 1- An object weighing 303 N in the air is immersed in water after being tied to a string connected to a balance. The scale now reads 267 N . Immersed in oil, the object appears to weigh 279 N . Find the density of the object. Answer in units of kg/m 3 PART 2- Find the density of the oil. Answer in units of kg/m3

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Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.