PLEASE HELPP A girl places a stick at an angle of 60.0° against a flat rock on a frozen pond. She pushes at
an angle and moves the rock horizontally for 2.00 m across the pond at a velocity of 4.00 m/s
and a power of 160.0 W. What force did she apply to the stick? How much work did she do?
Your response should include all of your work and a free-body diagram.
please show work

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.