A car travels with a velocity of 18km/hr, then it accelerates uniformly and travels a distance of 5m. If the velocity reached is 54 km/hr, find the acceleration and the time taken to travel this distance.

Explanation: Vi = 18k/hr   =  18 x 1000/3600  = 5/s

                      Vf = 54k/hr  =   54 x 1000/3600 = 15/s

                       S  =  5

                        a =   ?

                        t  =   ?

           BY USING NEWTON 3RD EQUATION OF MOTION

                        2aS= Vf^2-Vi^2

                           a =  Vf^2 - Vi^2/2S

                           a =   15^2 - 5^2/2(5)

                           a  =    20

           BY USING NEWTON  1st  EQUATION OF MOTION

                          Vf = Vi + at

                            t  =  Vf-Vi/a

                            t  =  15-5/20

                            t  =  10/20 = 1/2 sec = 0.5 sec

The acceleration of the car is 20 m/s²

This is the rate of change of velocity. To calculate the acceleration of the car, we use the formula below.

Formula:

Where:

Make a the subject of the equation

From the question,

Given:

Substitute these values above into equation 2

Hence, The acceleration of the car is 20 m/s².

Learn more about acceleration here:

explanation:

v=uf/(u-f)

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