Part 1 A merry-go-round rotates at the rate of

0.35 rev/s with an 86 kg man standing at

a point 2.5 m from the axis of rotation.

What is the new angular speed when the

man walks to a point 0 m from the center?

Consider the merry-go-round is a solid 50 kg

cylinder of radius of 2.5 m.

Answer in units of rad/s

Part 2

What is the change in kinetic energy due to

this movement?

Answer in units of J.

I'd go for the one that says that knees are fulcrums, lower legs are levers and the ankles hold loads.hope it ,happy homework/ study/ exam!

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

True will be your answer dude