Two forces F1 and F2 applied on a crate/box lying on a frictionless ,horizontal surface as shown in the diagram The magnitude of force is greater than that of force F2. Describe the state of motion of the crate

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

the ima (higher than 1m) will be greater than the ima with the height of 1m.

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: