A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 700 m/s. The barrel is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.09 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

An alpha particle with kinetic energy 12.5 mev makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude l = p0 b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.40×10−12 m. (assume that the lead nucleus remains stationary and that it may be treated as a point charge. the atomic number of lead is 82. the alpha particle is a helium nucleus, with atomic number 2.) what is the distance of closest approach?