A 62 kg student stands on a very light, rigid board that rests on a bathroom scale at each end, as shown in (Figure 1). What is the reading on the left scale?
What is the reading on the right scale?
Can someone help me with this question?

Step-Step Explanation:-

As the system is at equilibrium, this means that the reading on the scales have to add to the weight of the student, which means that:-

or

As we know that momentum of the system have to be zero, this means that the momentum for each scale is equal and then we have:-

Plugin this in the equation for forces, we have:-

Now we know the reading on the right scale, we plug it on the equation for the left scale.

Therefore, the reading on left scale is 151.9 N and the reading on right scale is 455.7 N.

trig 15.3 cos

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