A 215 N box is placed on an inclined plane that makes a 35.0 degree angle with the horizontal.  What applied force is needed to accelerate box up the incline at 0.470 m/s2 if the force of friction is 75.0 Newtons?

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Electrons have a negative charge if that's what you're asking