1) what is the potential energy at the end of the loop? 2)what is the kinetic energy at the end of the loop(based upon photogate time?

release the car and record the time from the photogate at the bottom of the hill and answer the top questions:
i attached an image that shows the recorded time

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

ingenuity says that the answer is 2.7 m.