What is the potential energy at the end of the loop? what is the kinetic energy at the end of the loop (based upon the photogate time) I PUT THE TIME ON THE PICTURE? oh also can you help me find the speed of the car at the bottom of the hill like i know speed is distance multiples by time but i don’t know what number to use for distance.. the same picture shows some data i just don’t know how to use it. thanks would be greatly appreciated

You can find results and justify them? you can test your hypothesis

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.