The acceleration of a train moving from rest and its speed reaches 36m/sec in 9 sec

4 m/s^2

Explanation:

The acceleration is defined as: Δv/Δt (the difference of the velocity over a time period in which happens that difference).

Remember that a difference is calculated by subtracting the initial value of a physical quantity from its final value.

In our case:

Δv = Vfinal - Vinitial = 36m/s - 0 m/s = 36m/s

Δt = 9s

a = Δv/Δt = 36m/s / 9s = 4m/s^2

answer: 0.20

explanation: this can only be the answew because all the other measuremnets are not close

unlike poles attract