A ball is projected at an angle of 30° above the horizontal with a speed of 35 m/s. What will be its approximate horizontal range across a level surface assuming no air resistance? F. 17.5 m
G. 54.2 m
H. 108 m
J. 125 m

The horizontal distance the ball travels before returning to the ground is 19.5 m

Step-by-step explanation:

Formula of range of horizontal distance =\frac{u^2 Sin 2 \theta}{g}gu2Sin2θ

Where u is the initial velocity

g is gravity

We are given that A ball is kicked off the ground with a velocity of 15 m/s at an angle of 30° horizontally.

So, u = 15 m/s

\theta = 30^{\circ}θ=30∘

g = 10

So, the horizontal distance the ball travels before returning to the ground = \frac{15^2 Sin 2(30^{\circ})}{10}=19.48 \sim 19.5 m10152Sin2(30∘)=19.48∼19.5m

Hence The horizontal distance the ball travels before returning to the ground is 19.5 m

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explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."

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