A closed tank contains water at the bottom and pressurized air at the top. The water discharges to the atmosphere from an orifice at the bottom of the tank. The height of water is 2.5 m and diameter of the orifice is 10 cm. Assume frictionless flow and the water discharge is 0.147 m/s. i) Calculate the air pressure in the tank. (7 marks)

ii) Determine the new height of water, If the tank is now open to the atmosphere. (3 marks)

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

one "light year" is the distance that light travels, through vacuum, in one julian year.   that's 365.25 days, of 24 hours each.