an iron cube of a mass of 480gram and a density of 8 gram per centimetre cube is suspended by a string such that it is half immersed in oil the density of oil is 0.9 gram per centimetre cube find the force acting on the String

i think the answer is a and b

i wish you luck

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form