V=VyV67.2 -8.2 m/s Part B
Now let's see if your prediction agrees with the experimental results. There isn't any data at y=-3.5 m, so you'll need to interpolate by zooming in
on the relationship between y velocity (W) and y displacement. You'll use Tracker's Data tool to help with this analysis. Follow these steps:
• Change the vy versus t graph to a vy versus y graph. (Click the t label on the horizontal axis and select y. position y-component from the
menu.)
• It's a little hard to see what's going on with this graph at y = -3.5, so zoom in. Double-click on the graph to open it up in the Data tool.
. Put your cursor on the point where the graph line intersects y = -3.5. Click and hold to read the vy at that point shown in a yellow box in the
bottom left comer).
What's the interpolated graph value of v, at y = -3.57 Comment on how well this value agrees with the value of v, that you calculated in part A of
this activity. Make a hypothesis about any notable difference.

Part a determine the magnitude of the x component of f using scalar notation. fx f x = nothing lb request answer part b determine the magnitude of the y component of f using scalar notation. fy f y = nothing lb request answer part c determine the magnitude of the z component of f using scalar notation. fz f z = nothing lb request answer provide feedback figure1 of 1a force vector acting on a ring attached to the ground is shown in the xyz space together with its x, y, and z components lying on the corresponding positive axes. the ring is located at the origin. force f is located in the first octant. f makes an angle of 60 degrees with its x component and an angle of 45 degrees with its y component. a force vector acting on a ring attached to the ground is shown in the xyz space together with its x, y, and z components lying on the corresponding positive axes. the ring is located at the origin. force f is located in the first octant. f makes an angle of 60 degrees with its x component and an angle of 45 degrees with its y component.

Imagine that someone pushes one marble toward a motionless marble. would there still be action-reaction forces involved in the collision? how might the marbles’ motions be changed? ?

(2) (a) you have a simple circuit that consists of only a battery (δvbat=1.5v) and two resistors with resistance r1=10ω and r2=5ω, connected in series with each other. what is the current running through the battery? (b) you re-arrange your circuit so now r2 is attached in parallel to r1 rather than in series. what is the current running through the battery? (c) you add an additional resistor r3=7ω on the same branch as r2. what is the current running through the battery? (d) what is the power dissipated in r3?