5) You pull a 5.0 kg wagon along a flat road. You exert a force of 80.0 N at an angle of 30.0 degrees above the horizontal while you move the wagon 10.0 m forward. The coefficient of friction between the wagon and road is 0.500. Calculate the work down by you and the work done by friction. This is what I've come to learn about the problem: Work done by you is just the component of the applied force that is parallel to the horizontal displacement. For work done by friction, remember that Fn is NOT equal to Fg in this case.

Can someone solve by showing the steps?