A bar 100 cm in length is subjected to an axial pull, such that the maximum stress is equal to 10^5 N! m^2. It's area of cross section is a bit 2 cm^2 over a length of the road 95 cm and for the middle 5 cm length it is only 1 cm^2. if E is a 200 GN/m^2,calculate the strain energy in the bar.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j

the answer is 100. i just did this lesson and got a 100% on it. : )

-fishtank