(part 1 of 2): An airplane flying parallel to the ground undergoes two consecutive displacements. The first is 84 km at 33.7◦ west of north, and the second is 160 km at 65.3◦ east of north. What is the magnitude of the plane’s total displacement? Answer in units of km.

(part 2 of 2): At what angle east of north is the plane’s total displacement? Answer in units of ◦.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..

+15-35=-20

going in opposite directions