Homework nr. 2 -
Due Tuesday, Oct. 19
1. (2 points) Write these values with the right prefixes:
0.008 m =
1.2 x 106 ) =
2. A block of 700 g is pulled from rest on a horizontal frictionless bench by a steady force Fand
travels 7.0 m in 3.5 s.
a) (2 points) What was the acceleration of the block?
b) (2 points) Calculate the value of the force.
3. A rocket has a mass of 900 kg.

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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