calculate the force acting on an electron of the charge 1.6×10-9c placed between two charged parallel plates where the electric field strength is 100N/C draw the shape and direction of the electric field between the plates and show the direction the electron will move

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

massxgravity x heght=weightxheight= pe

4900=490xh

h=10

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.