For Part A, Sebastian decided to use the copper cylinder. How would the magnitude of his q and ∆H compare if he were to redo Part A but this time using an aluminum cylinder of equal mass? Assume that the initial temperatures of the metals (Tm) and the initial temperatures of the water (Ti) were the same. Specific heat of copper: 0.385 J/g*K Specific heat of aluminum: 0.900 J/g*K Group of answer choices The magnitudes of his q and ∆H for the copper trial would be higher than the aluminum trial. The magnitudes of his q and ∆H for both trials would be the same The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

the maxium height is 34m/s