A charge q = 2.4 µC is placed at the point P shown below. What is the force on q (in N)? (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)

The magnitude of force between two charges q_1\ and\ q_2 separated by a distance r is

F=\frac{k|q_1||q_2|}{r^2}

where k=9×109Nm2/C2

The magnitude of force on charge q=2.7μC=2.7×10-6C by charge 1.5μC=1.5×10-6C which is 2.4+1.2=3.6m away from point P is

F_1=\frac{9\times10^9\times|2.7\times 10^{-6}|\times|1.5\times 10^{-6}|}{3.6^2}

F_1=2.813\times 10^{-3}\ N

The magnitude of force on q by -3.5μC charge which is 1.2m away is

F_2=\ frac {9\times10^9\times|2.7\times 10^{-6}|\times|-3.5\times 10^{-6}|}{1.2^2}

F_2=59.063\times 10^{-3}\ N

We know that like charges repel each other and unlike charges attract each other. q is repelled by 1.5μC and attracted by -3.5μC.

F_1 points to the right it is positive, F_2 points to the left it is negative. The net force on q is

F=+F_1-F_2

F=2.813\times 10^{-3}\ N-59.063\times 10^{-3}\ N

F=-56.25\times10^{-3}\ N

In two significant figures the answer is

F= -0.056  N

Explanation:

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.

scorpions are,

c.arachnids

  scorpions are animals in the order scorpiones, under the class arachnida, which makes them a distant cousin of spiders

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