At a wedding reception, you notice a small boy, 25 kg running and sliding on a dance floor. If the coefficient of friction between the boy’s pants and the floor is 0.15, what is the frictional force of the sliding boy?

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..

there are no atoms