given an oil droplet of mass 0.9mg and density 918kg/m^3 that spreads out into a circle of a radius 41.8cm on the water surface what is the diameter of the oil molecule​

The diameter of the oil molecule is  .

Explanation:

Mass of the oil drop =

Density of the oil drop =

Volume of the oil drop: v

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a =

Volume of the oil drop = v = Area × thickness

The thickness of the oil drop is  and so is the diameter of the molecule.

what are the options.

explanation:

answer: electrons