5. If 100N effort is required to lift a load of 300N in a lever of 1m and distance between fulcrums to load is 30 cm then, calculate, a) Effort distance b) MA c) VR d) Efficiency(n)​

effort distance =?

effort =100N

load =300N

lever =1m

load D =30cm

ma=?

vr=?

efficiency =?

we know that

effort distance =l ×ld

= 300×30

9000

ma= l ×e

= 100×300

= 30000

vr = ld ×ed

= 1×9000

=9000

efficiency =(ma÷vr)/100

(30000÷9000)×100

3.33×100

333

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