The declination of Procyon is 5 degrees on December 1. On December 10, it’s declination will be A.10 degrees, since 5 days have passed
B.20 degrees, since stars change their declination by 4 degrees each day
C. 0 degrees, since the declination is reduced by 1 degree every day
D.5 degree since the declination of stars does not change

Scientific classification

I'm pretty sure the answer is c 

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.