A car of 900 kg mass is moving at the velocity of 60 km/hr. It is brought into rest at 50 metre distance by applying brake. Now,
calculate the force required to stop the car. [Ans: 2500 N] class 9

2500N.

Explanation:

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98.4 m

explanation:

let s = distance up the plane  

then by conservation of energy  

1/2m(18.3)^2 = mg s sin(10)  

(18.3)^2 = 2g s sin(10)  

s = (18.3)^2/2gsin(10)  

= 98.39564526  

= 98.4 m

the strength of the electric field on the point charge= n/c

the electric field is given by

e=

q=6μc= 6 x 10⁻⁶c

r=100 m

e=

e=5.4 n/c

so the electric field on the point charge= 5.4n/c