39 liters of water at 20 °C are mixed with
21 liters of water at
60 °C. What is the
temperature of the
mixture?

Temperature of the mixture=8 °C

Explanation:

Let, Temperature of the mixture=t °C

Q₁ = Q₂

=> m₁SΔΘ₁ = m₂SΔΘ₂

=> 39 × (20+t) = 21 × (60-t)

∴ t = 8 °C

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option number c is the right answer.