10. Numerical problems: b. A stone is thrown vertically upwards with an initial velocity of 20 m/sec. find the maximum height it reaches and the time taken by it to reach the height. (g = 10 m/s2).

c. A car is moving at a rate of 72 km/hr. How far does the car move when it stops after 4 seconds?

d. A bus starts from rest. If the acceleration is 2 m/s2, find
1. the distance travelled.
2. the velocity after 2 seconds.

e. A stone is thrown vertically upward with the velocity of 25 m/s. How longo it take to reach the maximum height? Also calculate the height.

with process please

a)20 m,2s

Explanation:

Given

Initial velocity=20 m /sec

g=10 m/s square

v =0m/s

h =?

t =?

now,

v = U +gt

=v=20 +10t

Or,10t=20

Or,t=20

10

therfore ,2 s.

Again,

h=ut -1 gt square

2

Or, h=20×2-1×10(2)square (multiply and cut )2×5 =10

; 2

Or,40-5×4

therefore , 20m

seeing the graph would

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.