The gravitational force between two bodies is a10N when they are kept at a distance of 4 m how much gravitational force is produced when they are kept 2 apart ​

Gravitational force F=

r

2

Gm

1

m

2

Case (i) : Mass of one object is doubled i.e m

1

′

=2m

1

∴ F

′

=

r

2

G(2m

1

)m

2

⟹F

′

=2F

Thus gravitational force gets also doubled

Case (ii) : Distance between the objects is doubled i.e r

′

=2r

∴ F

′

=

(2r)

2

Gm

1

m

2

⟹F

′

=

4

F

Thus gravitational force gets reduced by 4 times.

Distance between the objects is tripled i.e r

′

=3r

∴ F

′

=

(3r)

2

Gm

1

m

2

⟹F

′

=

9

F

Thus gravitational force gets reduced by 9 times.

Case (iii) : Mass of both the objects are doubled i.e m

1

′

=2m

1

and m

2

′

=2m

2

∴ F

′

=

r

2

G(2m

1

)(2m

2

)

⟹F

′

=4F

Thus gravitational force becomes 4 times.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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