A wheel rotates without friction about a stationary horizontal axis at the center of the wheel. A constant tangential force equal to 90.0 N is applied to the rim of the wheel. The wheel has radius 0.150 m. Starting from rest, the wheel has an angular speed of 14.3 rev/s after 2.72 s. What is the moment of inertia of the wheel

the moment of inertia of the wheel is 0.408 kg.m²

Explanation:

Given;

tangential force applied to the wheel, f = 90 N

radius of the wheel, r = 0.15 m

initial angular speed of the wheel, ω₁ = 0

final angular speed of the wheel, ω₂ = 14.3 rev/s

time of motion of the wheel, t = 2.72 s

The tangential acceleration of the wheel is calculated as;

where;

is the angular acceleration

The mass of the wheel is calculated as;

F = ma

m = F/a

m = (90)/(4.96)

m = 18.15 kg

The moment of inertia of the wheel is calculated as;

I = mr²

I = 18.15 x (0.15)²

I = 0.408 kg.m²

Therefore, the moment of inertia of the wheel is 0.408 kg.m²

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diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.