A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.25 ms2.25 ms from an initial speed of 4.25 m/s4.25 m/s . What is the magnitude of the average contact force exerted on the leg, assuming the total mass of the hand and the forearm to be 1.75 kg1.75 kg

The force is 3305.6 N.

Explanation:

Final velocity, v = 0

time, t = 2.25 ms

initial velocity, u = 4.25 m/s

mass, m = 1.75 kg

Let the acceleration is a.

Use first equation of motion.

v = u + a t

0 = 4.25 + a x 0.00225

a = - 1888.9 m/s^2

The force is

F = ma

F = 1.75 x 1888.9

F = 3305.6 N

close lines strong magnet less close weaker

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.