A proton moves perpendicular to a uniform magnetic field at a speed of 1.75 107 m/s and experiences an acceleration of 2.25 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field.

B = 0.013(-j) T

Explanation:

Given that,

The speed of a proton,

Acceleration experienced by the proton,

We need to find the magnitude and the direction of the magnetic field. At equilibrium,

The velocity is in +z direction, force in +x direction, then the field must be in -y direction.

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.