When 100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C, about how much thermal energy is absorbed by the ethyl alcohol? (Assume the density of ethyl alcohol to be 0.790 g/mL.)

Q = 194.34  J

Explanation:

Given that,

100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C.

We need to find the amount of thermal energy  absorbed by the ethyl alcohol.

The density of ethyl alcohol is 0.790 g/mL.

The formula for heat absorbed is given by :

So, 194.34  J of thermal energy is absorbed by the ethyl alcohol.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j