A 134 kg merry-go-round has a radius of 1.6 m and it is rotating with an angular velocity of 0.3 rev/s. What is its angular velocity (in rev/s) after an at rest 83-kg person gets onto it by grabbing its outer edge

ω₂ = 0.134 rev/s

Explanation:

Conservation of angular momentum

L₁ω₁ = L₂ω₂

ω₂ = ω₁L₁/L₂

ω₂ = 0.3(½(134)(1.6²) / (½(134)(1.6²) + 83(1.6²)))

ω₂ = 0.3(½(134) / (½(134) + 83))

ω₂ = 0.134 rev/s

your answer would be fusion

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explanation: